16b^2=9

Solution for 16b^2=9 equation:

16b^2=9

We move all terms to the left:

16b^2-(9)=0

a = 16; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·16·(-9)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*16}=\frac{-24}{32}
=-3/4
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*16}=\frac{24}{32}
=3/4
$